If round-trip travel time doubles with the speed of sound held constant, what happens to the calculated depth?

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Sharpen your skills for the Davies Publishing SPI Test with targeted flashcards and multiple-choice questions, complete with hints and clarifications. Prepare thoroughly for success!

Multiple Choice

If round-trip travel time doubles with the speed of sound held constant, what happens to the calculated depth?

Explanation:
Depth is tied to how long the sound takes to go out and back, at a constant speed. The calculation uses depth = (speed of sound × round-trip time) / 2, so the round-trip time scales the depth directly when speed stays the same. If the round-trip time doubles, the depth also doubles because you’re multiplying by the same speed and then halving once for the two-way path—so doubling the time doubles the distance to the seabed. For instance, with 1500 m/s, a 0.2 s round trip gives 150 m depth, and 0.4 s gives 300 m depth.

Depth is tied to how long the sound takes to go out and back, at a constant speed. The calculation uses depth = (speed of sound × round-trip time) / 2, so the round-trip time scales the depth directly when speed stays the same. If the round-trip time doubles, the depth also doubles because you’re multiplying by the same speed and then halving once for the two-way path—so doubling the time doubles the distance to the seabed. For instance, with 1500 m/s, a 0.2 s round trip gives 150 m depth, and 0.4 s gives 300 m depth.

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