If the speed of sound in PZT increases, what happens to the frequency of sound produced by a pulsed wave transducer?

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Sharpen your skills for the Davies Publishing SPI Test with targeted flashcards and multiple-choice questions, complete with hints and clarifications. Prepare thoroughly for success!

Multiple Choice

If the speed of sound in PZT increases, what happens to the frequency of sound produced by a pulsed wave transducer?

Explanation:
In a pulsed-wave transducer, the emitted sound frequency is determined by the crystal’s thickness resonance. For a piezoelectric plate of thickness d vibrating in thickness mode, the fundamental frequency is f = v/(2d), where v is the speed of sound in the crystal. So, if the speed of sound in PZT increases, the resonance frequency increases in direct proportion. That means the sound produced becomes higher in frequency. The idea that it would stay the same, lower, or be inversely related doesn’t fit the resonance relationship f = v/(2d).

In a pulsed-wave transducer, the emitted sound frequency is determined by the crystal’s thickness resonance. For a piezoelectric plate of thickness d vibrating in thickness mode, the fundamental frequency is f = v/(2d), where v is the speed of sound in the crystal. So, if the speed of sound in PZT increases, the resonance frequency increases in direct proportion. That means the sound produced becomes higher in frequency. The idea that it would stay the same, lower, or be inversely related doesn’t fit the resonance relationship f = v/(2d).

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