What is the effect of increasing crystal diameter on beam divergence in the far field?

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Multiple Choice

What is the effect of increasing crystal diameter on beam divergence in the far field?

Explanation:
In the far field, diffraction from the crystal behaves like an aperture, and the angular spread of the beam is roughly theta ≈ lambda / D. So when the crystal diameter D increases, theta gets smaller and the beam becomes more collimated, meaning it diverges less. The total energy stays the same, but it is confined to a narrower solid angle. If you keep the wavelength fixed, this inverse relationship holds; changing the frequency (and thus the wavelength) would also affect divergence, but with diameter alone, the divergence decreases as diameter increases.

In the far field, diffraction from the crystal behaves like an aperture, and the angular spread of the beam is roughly theta ≈ lambda / D. So when the crystal diameter D increases, theta gets smaller and the beam becomes more collimated, meaning it diverges less. The total energy stays the same, but it is confined to a narrower solid angle. If you keep the wavelength fixed, this inverse relationship holds; changing the frequency (and thus the wavelength) would also affect divergence, but with diameter alone, the divergence decreases as diameter increases.

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